A) \[\frac{{{n}^{2}}}{e+1}\]
B) \[\frac{{{n}^{2}}}{e-1}\]
C) \[{{n}^{2}}\]
D) \[e.{{n}^{2}}\]
Correct Answer: C
Solution :
\[y=n\,\ell \,n\,x,\] \[n>1,\] \[n\in N\] \[A\,(n)=\int\limits_{1}^{e}{n\,\ell \,n\,\,x\,dx=n}\] \[\therefore \] \[A\,(n)+n\,A\,(n-1)={{n}^{2}}.\]You need to login to perform this action.
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