A) \[Co,Z=\text{ }27~\]
B) \[Iron,\,\,Z=26\]
C) \[Mn,\text{ }Z\text{ }=\text{ }25~\]
D) \[Ni,\text{ }Z\text{ }=\text{ }28\]
Correct Answer: A
Solution :
[A]\[\frac{1}{{{\lambda }_{a}}}=\frac{3R}{4}{{(Z-1)}^{2}}\] |
\[\Rightarrow (Z-1)=\sqrt{\frac{4}{3R{{\lambda }_{a}}}}\] |
\[=\sqrt{\frac{4}{3\times 1.1\times {{10}^{7}}\times 1.8\times {{10}^{-10}}}}\] |
\[\frac{200}{3}\sqrt{\frac{5}{33}}=\frac{78}{3}=26.\] |
\[\Rightarrow \,\,=\,27\] |
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