A) \[\frac{\varepsilon }{R}\]
B) \[\frac{\varepsilon }{2R}\]
C) \[\frac{\varepsilon }{5R}\]
D) \[\frac{\varepsilon }{4R}\]
Correct Answer: C
Solution :
[C]Just after switching, the capacitor will act like a conducting wire. So effective circuit will be |
By applying KVL at point P |
\[\frac{V-\varepsilon }{R}+\frac{V-\varepsilon }{R}+\frac{V}{2R}=0\] |
\[V=\frac{4\varepsilon }{5}\] |
So, current in the branch containing capacitor \[=\frac{\varepsilon }{5R}.\] |
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