A) \[2\text{ }v\text{ }sin\text{ }\beta \]
B) \[v\text{ }cos\text{ }2\text{ }\beta \]
C) \[2v\,\,sin\,\,\beta ~\]
D) \[v\sqrt{2}\]
Correct Answer: C
Solution :
[C]From image diagram |
\[={{\upsilon }_{{{I}_{2}}{{I}_{1}}}}=\sqrt{{{(v-v\cos 2\beta )}^{2}}+{{(v\sin 2\beta )}^{2}}}\] |
\[=2\text{v}\,\,\sin \beta \] |
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