A) \[0.250\]
B) \[0.125\]
C) \[0.100\]
D) \[0.075\]
Correct Answer: D
Solution :
[d]Mole fraction, \[X=\frac{\frac{w}{m}}{\frac{w}{m}+\frac{W}{M}}\] |
(Where w and m represent the mass and molar mass of solute and W and M represent the mass and molar mass of solvent) |
\[\frac{1}{x}=\frac{\frac{w}{m}+\frac{W}{M}}{\frac{w}{m}}\] |
\[\frac{1}{x}=1+\frac{W\times m}{M\times w}\times \frac{1000}{1000}\] |
\[\frac{1}{x}=1+\frac{1000}{M\times w}\left( \therefore MOlarity,m=\frac{w\times 1000}{m\times W} \right)\] |
\[=1+\frac{1000}{18\times 4.5}\] |
(\[\therefore \]molar mass of \[{{H}_{2}}O=18\]\[mo{{l}^{-1}}\])\[=1+\frac{1000}{81}=13.34\] |
\[x=\frac{1}{13.34}=0.075\] |
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