A) 4
B) \[2\sqrt{5}\]
C) 5
D) \[3\sqrt{5}\]
Correct Answer: C
Solution :
At point \[{{Q}_{1}}\,\,\,x=0\] |
\[\therefore \]in line \[5x-2y+6=0\] |
Put \[x=0\] \[\Rightarrow \] \[y=3\] |
\[\therefore Q(0,3)\] |
\[\therefore PQ=\sqrt{{{0}^{2}}+{{3}^{2}}+6(0)+6(3)-2}=5\] |
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