A) 4 s
B) 2 s
C) \[\frac{4}{\sqrt{21}}s\]
D) \[\frac{2}{\sqrt{11}}\,\,s\]
Correct Answer: B
Solution :
Relative to left initial velocity and acceleration of coin are 0 m/s and \[1m/{{s}^{2}}\]downward |
\[\therefore \,\,\,2=\frac{1}{2}(1)\,{{t}^{2}}\] or t=2 second |
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