A) \[6\pi {{a}_{0}}\]
B) \[4\pi {{a}_{0}}\]
C) \[2\pi {{a}_{0}}\]
D) None of these
Correct Answer: B
Solution :
| \[\because \,\,\,mv{{r}_{n}}=\frac{nh}{2\pi }\] and \[p=\frac{h}{\lambda }\] |
| \[=p{{r}_{2}}=\frac{2\times h}{2\times \pi }\] \[\Rightarrow \frac{h}{\pi }\] or \[\frac{h}{\lambda }.\,\,{{r}_{2}}=\frac{h}{\pi }\] \[\Rightarrow \lambda =\pi {{r}_{2}},\] |
| \[\therefore \,\,\,{{r}_{2}}=4{{a}_{0}};\] |
| \[\therefore \,\,\,\lambda =4{{a}_{0}}\pi \] |
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