A) \[N{{H}_{3}},\,\,{{N}_{2}},\,\,M{{g}_{3}}{{N}_{2}}\]
B) \[{{N}_{2}},\,\,N{{H}_{3}},\,\,MgNH\]
C) \[{{N}_{2}},\,\,{{N}_{2}}{{O}_{5}},\,\,Mg{{(N{{O}_{3}})}_{2}}\]
D) \[N{{H}_{3}},\,\,N{{O}_{2}},\,\,Mg{{(N{{O}_{2}})}_{2}}\]
Correct Answer: A
Solution :
\[Ca(NH)+2{{H}_{2}}O\to Ca{{(OH)}_{2}}+N{{H}_{3}}(g)\] |
\[\underset{(B)}{\mathop{2N{{H}_{3}}}}\,+3CaOC{{l}_{3}}\to \underset{(C)}{\mathop{{{N}_{2}}(g)}}\,+3CaC{{l}_{2}}+3{{H}_{2}}O\] |
\[\underset{(C)}{\mathop{{{N}_{2}}(g)}}\,+3Mg\to \underset{(D)}{\mathop{M{{g}_{3}}{{N}_{2}}}}\,\] |
\[\underset{(D)}{\mathop{M{{g}_{3}}{{N}_{2}}}}\,+\underset{(B)}{\mathop{6{{H}_{2}}O}}\,\to 3Mg{{(OH)}_{2}}+2N{{H}_{3}}\] |
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