In the arrangement shown in figure, coefficient of friction between the two blocks is \[\mu =\frac{1}{2}\] The force of friction acting between the two blocks is: |
A) 8 N
B) 10 N
C) 6 N
D) 4 N
Correct Answer: A
Solution :
Free body diagram of the two bodies are as follows |
Let acceleration of both the blocks towards left is a. Then |
\[a=\frac{f-2}{2}=\frac{20-f}{4}\] or \[2f-4=20-f\] or \[f=8N\] |
Maximum friction between the two blocks can be: |
\[{{f}_{\max }}=\mu mg\left( m=2kg \right)\] |
\[=\left( 0.5 \right)\left( 2 \right)\left( 10 \right)=10N\] |
Now since \[f<{{f}_{\max }}\] |
Therefore, friction force between the two blocks is 8N. |
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