A) circle
B) parabola
C) straight line
D) ellipse
Correct Answer: C
Solution :
\[{{\overrightarrow{v}}_{com}}=\frac{{{m}_{1}}{{\overrightarrow{v}}_{1}}+{{m}_{2}}{{\overrightarrow{v}}_{2}}}{{{m}_{1}}+{{m}_{2}}}\] |
\[=\frac{\overrightarrow{{{v}_{1}}}+{{\overrightarrow{v}}_{2}}}{2}\] \[\left( {{m}_{1}}={{m}_{2}} \right)\] |
\[=\left( \overset{\hat{\ }}{\mathop{i}}\,+\overset{\hat{\ }}{\mathop{j}}\, \right)m/s\] |
Similarly \[{{\overrightarrow{a}}_{com}}=\frac{\overrightarrow{a}+{{\overrightarrow{a}}_{2}}}{2}=\frac{3}{2}\left( \overset{\hat{\ }}{\mathop{i}}\,+\overset{\hat{\ }}{\mathop{j}}\, \right)m/{{s}^{2}}\] |
Since, \[{{\overrightarrow{v}}_{com}}\] is parallel to \[{{\overrightarrow{a}}_{com}}\] the path will be a straight line. |
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