In the circuit shown in figure potential difference between A and B is: |
A) 30 V
B) 60 V
C) 10 V
D) 90 V
Correct Answer: C
Solution :
\[\frac{{{v}_{1}}}{{{v}_{2}}}=\frac{\left( \frac{15}{4} \right)C}{C}=\frac{15}{4};\,\,\,\therefore \,\,\,\,\,\,{{V}_{2}}=\left( \frac{4}{19} \right)(190)=40V\] |
Now this 40V is distributed in C and 3C in the |
ratio of \[\frac{3}{1}\] |
\[\therefore \,\,\,\,\,\,{{V}_{AB}}=10V\] |
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