A) \[{{S}_{1}}=\{-2,-1\};{{S}_{2}}=\{0\}\]
B) \[{{S}_{1}}=\{-2,1\};{{S}_{2}}=\{0\}\]
C) \[{{S}_{1}}=\{-2,1\};{{S}_{2}}=\{-1\}\]
D) \[{{S}_{1}}=\{-2,2\};{{S}_{2}}=\{0\}\]
Correct Answer: B
Solution :
\[y=9{{x}^{4}}+12{{x}^{3}}-36{{x}^{2}}-25\] |
\[\frac{dy}{dx}=36{{x}^{3}}+36{{x}^{2}}-72x\] |
\[=36x({{x}^{2}}+x-2)\] |
\[=36x(x+2)(x-1).\] |
\[(-2,1)\to \]points of minima |
\[(0)\to \]point of maxima. |
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