question_answer

Let the equation of a line is \[3x+5y=15\] and a point P on this line is equidistant from \[x\] and y axis In which quadrant the point P lies?

A) \[1st\]   

B) \[3rd\]

C) \[4th\]

D)  None of these

Correct Answer: A

Solution :

From the figure,

Intersection of the original line with \[y=x\] and \[v=-x\] will give desired points P in 1st and 2nd quadrant.