A) \[x-y-z=0\]
B) \[2x-z=0\]
C) \[x+2z-1=0\]
D) \[x-z-1=0\]
Correct Answer: A
Solution :
\[{{P}_{1}}+\lambda {{P}_{2}}=0\] |
\[(2x-y-4)+\lambda (y+2z-4)=0\] |
It passes through (1, 1, 0)\[\Rightarrow \]\[1+\lambda =0\]\[\Rightarrow \] \[\lambda =-1\] |
equation of plane is \[x-y-z=0.\] |
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