A) 14
B) 6
C) 4
D) 8
Correct Answer: D
Solution :
\[\frac{{{2}^{403}}}{15}\,=\,\frac{8(16)}{15}\,=\,\frac{8{{(1+15)}^{100}}}{15}\]\[=\,\frac{8}{15}[1+15\alpha ]\] For some\[\alpha \in N\]\[=\,\left( \alpha +\frac{8}{15} \right)\] \[\therefore \] Fractional part \[=\,\frac{8}{15}\,=\,\frac{k}{15}\] \[\Rightarrow \] \[k=8.\]You need to login to perform this action.
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