| \[C{{u}^{+}}+{{e}^{-}}\to Cu,E{}^\circ ={{x}_{1}}\] volt; |
| \[C{{u}^{2+}}+2{{e}^{-}}\to Cu,\] \[E{}^\circ ={{x}_{2}}\] volt, then for |
| \[C{{u}^{2+}}+{{e}^{-}}\to C{{u}^{+}},\] \[E{}^\circ \](volt) will be - |
A) \[{{x}_{1}}-2{{x}_{2}}\]
B) \[{{x}_{1}}+2{{x}_{2}}\]
C) \[{{x}_{1}}-{{x}_{2}}\]
D) \[2{{x}_{2}}-{{x}_{1}}\]
Correct Answer: D
Solution :
[D]| \[C{{u}^{+}}+{{e}^{-}}\,\,\xrightarrow{{}}\,\,Cu,\,\,E{}^\circ ={{x}_{1}}\,\,Volt\] |
| \[C{{u}^{2+}}+2{{e}^{-}}\,\,\xrightarrow{{}}\,\,Cu,\,\,{{x}_{2}}\,\,\,Volt\] |
| \[Cu\,\,\xrightarrow{{}}\,\,C{{u}^{+}}{{e}^{-}}-{{x}_{1}}\,\,\,Vo\operatorname{lt}\] |
| \[C{{u}^{2+}}+{{e}^{-}}\,\,\xrightarrow{{}}\,\,C{{u}^{+}}-2\times {{x}_{2}}\times f+1\times {{x}_{1}}\times f\]\[=-\,1\,\,\times \,\,E{}^\circ \,\,\times \,\,f\] |
| \[E{}^\circ =2{{x}_{2}}-{{x}_{1}}\] |
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