A) 2 A
B) \[2\sqrt{2}\,A\]
C) \[0.5\,A\]
D) \[\sqrt{0.4}\,A\]
Correct Answer: B
Solution :
\[{{I}_{R}}=\frac{V}{R}=\frac{200}{100}=2A\] |
\[I'=\frac{V}{{{X}_{L}}-{{X}_{C}}}=\frac{200}{100}=2A\] |
\[I=\sqrt{{{I}_{R}}^{2}+I{{'}^{2}}}=2\sqrt{2}\,\,Amp.\] |
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