A) \[\frac{mg}{k}\]
B) \[\frac{2mg}{k}\]
C) \[\frac{3mg}{k}\]
D) \[\frac{4mg}{k}\]
Correct Answer: B
Solution :
Just after cutting the string extension in spring\[=\frac{3mg}{k}\] |
The extension in the spring when block is in mean position\[=\frac{mg}{k}\] |
\[\therefore \] Amplitude of oscillation\[A=\frac{3mg}{k}-\frac{mg}{k}=\frac{2mg}{k}.\] |
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