| What is correct for stability order- of isomers |
| (I) Cyclohexan 1, 3 diol aa > ee conformer conformer |
| (II) Cylco octene cis > trans isomer Isomers |
| (III) 1, 2 dimethyl cyclobutane trans > cis isomer Isomer |
| (IV) Ethan-1, 2 diol anti form > gauch form |
| (V) Methyl cyclohexan Axial conformer > equatorial conformer |
A) I, III, IV, V only
B) I, II, III only
C) I, III, IV only
D) All are correct
Correct Answer: B
Solution :
[B]| \[\to \](I) is correct due to H bonding |
| \[\to \](II) In cycloalkene cis isomer is stable upto 8-10 membering. |
| \[\to \](III) trans more stable than cis. |
| \[\to \](IV) Due to H bond Gauche more stable |
| \[\to \](V) Generally equatorial conformer more stable than axial conformer. |
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