A) \[\frac{5\pi }{6}\]
B) \[\frac{2\pi }{3}\]
C) \[\frac{3\pi }{4}\]
D) \[\pi \]
Correct Answer: B
Solution :
\[\theta \in \left( -\frac{\pi }{2},\pi \right)\] |
\[\frac{3+2i\sin \theta }{1-2i\sin \theta }\] is purely imaginary |
\[\Rightarrow \] \[3-4{{\sin }^{2}}\theta =0\] |
\[\Rightarrow \] \[{{\sin }^{2}}\theta =\frac{3}{4}\] |
\[\theta =n\pi \pm \frac{\pi }{3}\]\[\Rightarrow \] \[\theta =\frac{-\pi }{3},\]\[\frac{\pi }{3},\]\[\frac{2\pi }{3}.\] |
You need to login to perform this action.
You will be redirected in
3 sec