A) \[10\sqrt{2}\,\,m/s\]
B) \[10\sqrt{3}\,\,m/s\]
C) 20 m/s
D) 25 m/s
Correct Answer: B
Solution :
The pebble is at same distance from top and base of the tower after it falls down by a distance \[h=10\,m.\] |
Applying conservation of energy. |
\[\frac{1}{2}m{{v}^{2}}=\frac{1}{2}m{{u}^{2}}+mgh\] |
or \[{{v}^{2}}={{u}^{2}}+2gh=100+2\times 10\times 10=300\] |
\[\therefore \] \[v=10\sqrt{3}\,m/s.\] |
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