A) \[a+b=2\sqrt{c}\]
B) \[abc=1\]
C) \[{{a}^{2}}=c\]
D) \[a{{b}^{2}}=c\]
Correct Answer: B
Solution :
\[T=\frac{2\pi m}{qB},\] \[p=\frac{2\pi m}{qB}v\cos \theta ,\] \[R=\frac{mv\sin \theta }{qB}\] |
\[a=\frac{\cos {{\theta }_{1}}}{\cos {{\theta }_{2}}},\] \[b=\frac{sin{{\theta }_{1}}}{sin{{\theta }_{2}}},\] \[c=1\] |
\[a=\sqrt{3},\] \[b=\frac{1}{\sqrt{3}},\] \[c=1.\] |
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