A)
B)
C)
D)
Correct Answer: A
Solution :
[a] In step 1, when phenol reacts with chloroform in presence of \[NaOH\] then salicyaldehyde is formed. This reaction is known as Reimer-Tiemann reaction In step 2, the formed salicylaldehyde then undergoes Cannizzro reaction with formaldehyde in presence of strong base to give an oxidised product (minor) and reduced product (major).You need to login to perform this action.
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