KVPY Sample Paper KVPY Stream-SX Model Paper-4

  • question_answer
    Calculate the rate of loss of heat through a glass window of area \[1000{{\operatorname{cm}}^{2}}\]and thickness 0.4 cm when temperature inside is \[37{}^\circ C\] and outside is \[-5{}^\circ C.\]Coefficient of thermal conductivity of glass is \[2.2\times {{10}^{-3}}cal\,{{s}^{-1}}c{{m}^{-1}}{{K}^{-1}}.\]

    A) \[450cal\,s-1\]                

    B) \[231cals-1\]

    C) \[439cal\,s-1\]                

    D) \[650cal\,s-1\]

    Correct Answer: B

    Solution :

    [b]
    Here, \[\operatorname{A}=1000c{{m}^{2}},x=0.4\operatorname{cm}\]
    \[{{T}_{1}}-{{T}_{2}}=37-(-5)=42{}^\circ C\]
    \[K=2.2\times {{10}^{-3}}cal\,{{s}^{-1}}c{{m}^{-1}}{{K}^{-1}}\]
    Rate of loss of heat, \[=H=\frac{Q}{t}=\frac{KA\left( {{T}_{1}}-{{T}_{2}} \right)}{x}\]\[=\frac{2.2\times 1{{0}^{-3}}cal\,{{s}^{-1}}c{{m}^{-1}}{{K}^{-1}}\times 1000c{{m}^{-2}}\times 42}{0.4cm}\]\[=231cal{{s}^{-1}}\]


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