A) \[{{N}_{2}}{{O}_{5}}\]
B) \[N{{H}_{3}}\]
C) \[{{N}_{2}}{{O}_{3}}\]
D) \[HN{{O}_{3}}\]
Correct Answer: C
Solution :
[c]\[{{N}_{2}}{{O}_{3}}\] dissolves in water giving a pale blue solution of \[HN{{O}_{2}}\] which decolorises \[KMn{{O}_{4}}\]and oxidises KI to \[{{I}_{2}}.\] |
\[{{N}_{2}}{{O}_{3}}+{{H}_{2}}O\xrightarrow{{}}\underset{\text{Pale}\,\text{blue}}{\mathop{HN{{O}_{2}}}}\,\] |
\[HN{{O}_{2}}\]is a reducing agent \[MnO_{4}^{-}\xrightarrow{HN{{O}_{2}}}M{{n}^{2+}}\] |
\[HN{{O}_{2}}\]is also an oxidising agent \[{{I}^{-}}\xrightarrow{HN{{O}_{2}}}{{I}_{2}}\] |
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