A) \[Cl\]
B) \[C{{r}^{3+}}\]
C) \[M{{n}^{2+}}\]
D) \[MnO_{4}^{-}\]
Correct Answer: D
Solution :
[d] Higher the standard reduction potential, better is the oxidising agent. Among the given options, \[E_{MnO_{4}^{-}/M{{n}^{2+}}}^{{}^\circ }\] is highest, hence \[MnO_{4}^{-}\] is the strongest oxidising agent.You need to login to perform this action.
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