A) \[Na\]
B) \[Mg\]
C) \[Ca\]
D) \[Be\]
Correct Answer: C
Solution :
[c] \[\underset{A}{\mathop{3M}}\,+{{N}_{2}}\xrightarrow{{}}\underset{B}{\mathop{{{M}_{3}}{{N}_{2}}}}\,\] \[\underset{B}{\mathop{{{M}_{3}}{{N}_{2}}}}\,+6{{H}_{2}}O\xrightarrow{{}}\underset{C}{\mathop{3M{{(OH)}_{2}}}}\,+\underset{D}{\mathop{2N{{H}_{3}}}}\,\] \[\underset{C}{\mathop{M{{(OH)}_{2}}}}\,+C{{O}_{2}}\xrightarrow{{}}\underset{D}{\mathop{MC{{O}_{3}}}}\,+{{H}_{2}}O\] M may be either \[Ca\] or Ba. It is not magnesium because \[Mg{{(OH)}_{2}}\] has very low solubility in water. Thus, the correct option is [c].You need to login to perform this action.
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