A) \[0.70\operatorname{V},4.28\operatorname{V}\]
B) \[3.58\operatorname{V},4.28\operatorname{V}\]
C) \[5.35\operatorname{V},2.14\operatorname{V}\]
D) \[3.58\operatorname{V},9.3\operatorname{V}\]
Correct Answer: B
Solution :
[b]\[\frac{x-10}{20}+\frac{x-0}{10}+\frac{x-9.3}{10}=0\] |
\[x-10+2x+2x-18.6=0\Rightarrow 5x=28.6\] |
\[x=\frac{28.6}{5}=5.72V\] |
\[{{\operatorname{V}}_{10\Omega }}=9.3-5.72=3.58\] |
\[{{\operatorname{V}}_{20\Omega }}=10-5.72=4.28\] |
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