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KVPY Sample Paper KVPY Stream-SX Model Paper-4

  • question_answer
    Given, \[E_{C{{r}^{3+}}/Cr}^{{}^\circ }=-0.74V;\] \[E_{MnO_{4}^{-}/M{{n}^{2+}}}^{{}^\circ }=1.51V\] \[E_{CrO_{7}^{2-}/C{{r}^{3+}}}^{{}^\circ }=1.33V;\] \[E_{Cl/C{{l}^{-}}}^{{}^\circ }=1.36V\] Based on the data given above strongest oxidizing agent will be

    A) \[Cl\]                            

    B) \[C{{r}^{3+}}\]

    C) \[M{{n}^{2+}}\]                    

    D) \[MnO_{4}^{-}\]

    Correct Answer: D

    Solution :

    [d] Higher the standard reduction potential, better is the oxidising agent. Among the given options, \[E_{MnO_{4}^{-}/M{{n}^{2+}}}^{{}^\circ }\] is highest, hence \[MnO_{4}^{-}\] is the strongest oxidising agent.


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