A)
B)
C)
D)
Correct Answer: B
Solution :
[B]\[{{\log }_{3}}\left| 2z-1 \right|>{{\log }_{3}}\left| 2z+1 \right|\] |
\[\Rightarrow (2z-1)(2\bar{z}-1)>(2z+1)(2\bar{z}+1)\] |
\[\Rightarrow 4{{\left| \,z\, \right|}^{2}}-2\,(z+\bar{z})+1>4{{\left| \,z\, \right|}^{2}}+2\,(z+\bar{z})+1\] |
\[\Rightarrow 4.2\operatorname{Re}(z)<0\] |
\[\Rightarrow \operatorname{Re}(z)<0\] |
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