• question_answer For silver ${{C}_{p}}(J{{K}^{-\,1}}\,mo{{l}^{-\,1}})=23+0.01\,T.$ If the temperature (T) of 3 moles of silver is raised from 300 K to 1000 K at 1 atm pressure, the value of AH will be close to: A) 13 kJ                 B) 16 kJ C) 62 kJ     D) 21 kJ

 ${{C}_{p}}=23+0.01\,T$ $n=3$moles ${{T}_{1}}=300K$ ${{T}_{2}}=1000K$ $\Delta H=n{{C}_{p}}\Delta T$ $\Delta H=n\int\limits_{{{T}_{1}}}^{{{T}_{2}}}{{{C}_{p}}}\Delta T=3\int\limits_{300}^{1000}{(23+0.01T)dT}$$=3\int\limits_{300}^{100}{\left( 23T+\frac{0.01{{T}^{2}}}{2} \right)}$= 61.95 KJ/mle = 62 KJ/mole.