A) \[S={{\left( \frac{{{K}_{sp}}}{216} \right)}^{\text{1/7}}}\]
B) \[S={{\left( \frac{{{K}_{sp}}}{6912} \right)}^{\text{1/7}}}\]
C) \[S={{\left( \frac{{{K}_{sp}}}{144} \right)}^{\text{1/6}}}\]
D) \[S={{\left( \frac{{{K}_{sp}}}{929} \right)}^{\text{1/9}}}\]
Correct Answer: B
Solution :
\[Z{{r}_{3}}{{(P{{O}_{4}})}_{4}}\] \[{{K}_{sp}}={{(3S)}^{3}}{{(4S)}^{4}}\] \[\Rightarrow \] \[{{K}_{sp}}=6912{{S}^{7}}\] \[S={{\left( \frac{{{K}_{sp}}}{6912} \right)}^{1/7}}.\]You need to login to perform this action.
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