A) 5 m/s
B) 2.5 m/s
C) 2 m/s
D) 4 m/s
Correct Answer: A
Solution :
[A] During motion force acting on particle only in downward direction i.e. mg so only its vertical velocity change during the motion \[a=\frac{mg}{m}=g\,\,downward\] \[{{v}_{y}}={{u}_{y}}+gt\] \[{{v}_{y}}-{{u}_{y}}=gt\] \[\Delta v=gt=10\times 0.5=5m/\sec \]You need to login to perform this action.
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