A) Zero
B) \[\frac{Qqd}{2\pi {{\in }_{0}}{{\ell }^{3}}}\]
C) \[\frac{Qqd}{\pi {{\in }_{0}}{{\ell }^{3}}}\]
D) \[\frac{Qqd}{4\pi {{\in }_{0}}{{\ell }^{3}}}\]
Correct Answer: A
Solution :
[B] The two plates acts as a dipoleYou need to login to perform this action.
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