question_answer

In the above circuit, \[C=\sqrt{\frac{3}{2}}\mu F,\] \[R=20\Omega ,\] \[L=\frac{\sqrt{3}}{10}H\] and \[{{R}_{1}}=10\Omega .\]Current in \[L-{{R}_{1}}\]path is \[{{I}_{1}}\] and \[C-{{R}_{2}}\]Path is \[{{I}_{2}}.\] The voltage of A.C. source is given by, \[V=200\sqrt{2}\sin (100t)\] volts. The phase difference between \[{{I}_{1}}\] and \[{{I}_{2}}\]is:

A) \[60{}^\circ \]                          

B) \[30{}^\circ \]

C) \[90{}^\circ \]                          

D) None of These