A) 3/4
B) ¼
C) 1/3
D) 1/8
Correct Answer: A
Solution :
The given condition can be written |
\[{{({{\cos }^{2}}\alpha +{{\sin }^{2}}\alpha )}^{3}}-3{{\sin }^{2}}\alpha {{\cos }^{2}}\alpha \,({{\cos }^{2}}\alpha +si{{n}^{2}}\alpha )+\]\[ksi{{n}^{2}}2\alpha =1.\] |
\[\Rightarrow \] \[(-\,3/4)si{{n}^{2}}2\alpha +ksi{{n}^{2}}2\alpha =0,\] |
showing that \[k=3/4.\] |
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