A) 1700 nm
B) 2020 nm
C) 220 nm
D) 250 nm
Correct Answer: D
Solution :
\[5.6eV-0.7eV=4.9eV\] |
\[=\frac{12410eV-A{}^\circ }{\lambda }\] |
\[=\frac{12410eV-A{}^\circ }{\lambda }\] |
\[\lambda =\frac{12410eV-A{}^\circ }{4.9eV}\approx 250nm.\] |
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