A) 250 ohm
B) 200 ohm
C) 6200 ohm
D) 6250 ohm
Correct Answer: B
Solution :
\[{{V}_{o}}={{i}_{{{g}_{o}}}}({{R}_{G}}+R)\] |
\[{{i}_{go}}=4\times {{10}^{-4}}\times 25={{10}^{-2}}A\] |
\[{{V}_{o}}=2.5V\] |
\[{{R}_{g}}+R=\frac{{{V}_{O}}}{{{i}_{{{g}_{o}}}}}=\frac{2.5}{{{10}^{-2}}}=250\] |
\[\Rightarrow \] \[R=200\Omega .\] |
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