A) Propanal
B) butanal
C) \[n-\]butyl alcohol
D) \[n-\]propyl alcohol.
Correct Answer: D
Solution :
\[C{{H}_{3}}C{{H}_{2}}OH\xrightarrow{P+{{I}_{2}}}C{{H}_{3}}C{{H}_{2}}I\]\[\xrightarrow[\operatorname{Ether}]{\operatorname{Mg}}{{\operatorname{CH}}_{3}}\underset{\overset{{}}{\mathop{(B)}}\,}{\mathop{C}}\,{{H}_{2}}MgI\xrightarrow{\operatorname{HCHO}}\]You need to login to perform this action.
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