A) \[276pm\]
B) \[138pm\]
C) \[552pm\]
D) \[415pm\]
Correct Answer: C
Solution :
in a fcc lattice, the distance between the cation and anion is equal to the sum of their radii, which is equal to half of the edge length of unit cell, |
\[i.e.{{r}^{+}}+{{r}^{-}}=\frac{a}{2}\] (where a=edge length) |
\[{{r}^{+}}=95pm,{{r}^{-}}=181pm\] |
\[Edge\text{ }length\text{ }=2{{r}^{+}}+2{{r}^{-}}=(2\times 95+2\times 181)\] |
\[pm=(190+362)pm=552pm.\] |
You need to login to perform this action.
You will be redirected in
3 sec