A) a precipitate is formed which does not dissolve in excess of ammonium hydroxide
B) A precipitate is formed which dissolves in excess of ammonia solution
C) No precipitate is formed
D) None of these
Correct Answer: A
Solution :
\[A{{l}_{2}}{{(S{{O}_{4}})}_{3}}+6N{{H}_{4}}OH\xrightarrow{{}}\]\[2Al{{(OH)}_{3}}+3{{(N{{H}_{4}})}_{2}}S{{O}_{4}}\] |
\[Al{{(OH)}_{3}}+NaOH\to N{{a}^{+}}{{[Al{{(OH)}_{4}}]}^{-}}\] |
Soluble complex it is insoluble in \[N{{H}_{4}}OH\] |
You need to login to perform this action.
You will be redirected in
3 sec