A) \[\frac{{{x}^{3}}}{2}+{{x}^{2}}+2x+c\]
B) \[\frac{{{x}^{3}}}{3}+{{x}^{2}}+2x+c\]
C) \[\frac{{{x}^{3}}}{3}+\frac{{{x}^{2}}}{2}+x+c\]
D) \[\frac{{{x}^{3}}}{3}+{{x}^{2}}-2x+c\]
Correct Answer: B
Solution :
\[{{x}^{4}}+4={{x}^{4}}+4+4{{x}^{2}}-4{{x}^{2}}\,{{({{x}^{2}}+2)}^{2}}-{{(2x)}^{2}}\]\[=({{x}^{2}}-2x+2)\] |
\[\therefore \] \[I=\int{({{x}^{2}}+2x+2)\,dx=\frac{{{x}^{3}}}{3}+{{x}^{2}}+2x+c}\] |
You need to login to perform this action.
You will be redirected in
3 sec