A) 1 T
B) \[{{10}^{2}}\,\,T\]
C) \[{{10}^{-2}}\,\,T\]
D) \[{{10}^{-4}}\,T\]
Correct Answer: D
Solution :
\[I=\frac{B_{o}^{2}}{2{{\mu }_{o}}}\times C\] \[B_{o}^{2}=I\times 2{{\mu }_{o}}\times C\] \[B_{o}^{2}=\frac{{{10}^{3}}\times 2\times 4\pi \times {{10}^{-7}}}{3\times {{10}^{8}}}\] \[{{B}_{0}}\approx {{10}^{-4}}T.\]You need to login to perform this action.
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