A) \[{{\operatorname{Na}}_{2}}\operatorname{O}\]
B) \[{{\operatorname{Na}}_{2}}{{\operatorname{O}}_{2}}\]
C) \[{{\operatorname{Li}}_{2}}O\]
D) \[{{\operatorname{KO}}_{2}}\]
Correct Answer: D
Solution :
| \[{{\operatorname{Na}}_{2}}O+{{H}_{2}}O\xrightarrow{{}}2NaOH\] |
| \[{{\operatorname{Li}}_{2}}O+{{H}_{2}}O\xrightarrow{{}}2LiOH\] |
| \[{{\operatorname{Na}}_{2}}{{O}_{2}}+2{{H}_{2}}O\xrightarrow{{}}NaOH+{{H}_{2}}{{O}_{2}}\] |
| \[{{\operatorname{Li}}_{2}}{{O}_{2}}+2{{H}_{2}}O\xrightarrow{{}}LiOH+{{H}_{2}}{{O}_{2}}\] |
| Superoxide react with water to give hydroxides, hydrogen peroxide and oxygen |
| \[2K{{O}_{2}}+2{{H}_{2}}O\xrightarrow{{}}2KOH+{{H}_{2}}{{O}_{2}}+{{O}_{2}}\] |
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