A) 516
B) 2066
C) 5033
D) 1033
Correct Answer: D
Solution :
using gas equation; \[PV=nRT\] |
Total no. of moles of gas in the mixture (n) \[=\frac{PV}{RT}=\frac{6\times 3}{0.0821\times 300}=0.7308mol.\] |
Thus no. of moles of unknown gas \[=0.7308-0.7=0.0308mol.\] |
Now we know that \[\frac{{{r}_{1}}}{{{r}_{2}}}=\frac{moles\,of\,hydrogen\,gas}{moles\,of\,unknown\,gas}=\frac{0.7}{0.0308}\] |
Also we know that \[\frac{{{r}_{1}}}{{{r}_{2}}}=\frac{\sqrt{{{M}_{2}}}}{\sqrt{{{M}_{1}}}}\] |
\[\therefore \]\[{{M}_{2}}={{\left( \frac{{{r}_{1}}}{{{r}_{2}}} \right)}^{2}}\times {{M}_{1}}\] |
Or \[{{M}_{2}}={{\left( \frac{0.7}{0.0308} \right)}^{2}}\times 2=1033\] |
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