A) \[\left( \frac{1}{2},2,3 \right)\]
B) (1, 1, 3)
C) \[\left( \frac{1}{2},2,0 \right)\]
D) (1, 1, 0)
Correct Answer: B
Solution :
Normal to there 2 curves are |
\[y=m(x-c)-2bm-b{{m}^{3}}\] |
\[y=mx-4am-2a{{m}^{3}}\] |
If they how a common normal |
\[(c+2b)-4a=(2a-b){{m}^{2}}\] |
(\[m=0\]corresponds to axis) |
\[\Rightarrow \] \[{{m}^{2}}=\frac{c}{2a-b}-2>0\] |
\[\frac{c}{2a-b}>2\] |
According to the question answer is (1, 2, 3, 4) but may be in question they want common normal other than x-axis, hence answer is [B]. |
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