A) Both P(3) and P(5) are true
B) P(3) is false but P(5) is true
C) Both P(3) and P(5) are false
D) P(5) is false but P(3) is true Physics
Correct Answer: A
Solution :
\[P(n)={{n}^{2}}+41\] |
\[P(3)=9-3+41=47\] |
\[P(5)=25-5+47+61\] |
Hence, \[P(3)\]and\[P(5)\]both are prime. |
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