A) Re (z) = 0
B) \[\left| z \right|=\sqrt{\frac{5}{2}}\]
C) \[\left| z \right|=\frac{1}{2}\sqrt{\frac{17}{2}}\]
D) None of these
Correct Answer: D
Solution :
\[\left| \frac{3{{z}_{1}}}{2{{z}_{2}}} \right|=2\] |
Let, \[\frac{3{{z}_{1}}}{2{{z}_{2}}}=2\cos \theta +2(\sin \theta )i\] |
\[\Rightarrow \] \[\frac{2{{z}_{2}}}{3{{z}_{1}}}=\frac{1}{2}\cos \theta -\frac{1}{2}(sin\theta )\] |
Given, \[z=\frac{2{{z}_{1}}}{3{{z}_{2}}}+\frac{3{{z}_{2}}}{2{{z}_{1}}}=\frac{5}{2}\cos \theta +\frac{3}{2}(\sin \theta )i\] |
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