A) \[2\sqrt{5}\]
B) 4
C) 5
D) \[\sqrt{57}\]
Correct Answer: C
Solution :
Tangent at\[(1,-1)\]is |
\[x(1)+y(-1)+2(x+1)-3(y-1)-12=0\] |
\[=3x-4y=7\] |
Required circle is |
\[{{(x-1)}^{2}}+{{(y+1)}^{2}}+\lambda (3x-4y-7)=0\] |
It passes through\[(4,0)\] |
\[\Rightarrow \] \[9+1+\lambda (12-7)=0\] |
\[\Rightarrow \] \[\lambda =-2\] |
\[\Rightarrow \]Required circle is\[{{x}^{2}}+{{y}^{2}}-8x+10y+16=0\] |
\[\Rightarrow \]Radius\[=\sqrt{16+25-16}=5\] |
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